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![What is [math]x^2+\frac{1}{x^2}[/math], given [math]x+\frac{1}{x}= 1[/math]? - Quora](https://qph.cf2.quoracdn.net/main-qimg-942892bd84d047350865de01a1f205be.webp "What is [math]x^2+\frac{1}{x^2}[/math], given [math]x+\frac{1}{x}= 1[/math]? - Quora")
What is [math]x^2+\frac{1}{x^2}[/math], given [math]x+\frac{1}{x}= 1[/math]? - Quora
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![The value of [1+ 1/(x+1)][1+1/(x+2)][1+1/(x+3)][1+1/(x+4)] is (a) (x+5)/(x+1) (b) (x+1)/(x+5) (c) 1+1/(x+5) (d) 1/(x+5)](https://d10lpgp6xz60nq.cloudfront.net/ss/web/157699.jpg "The value of [1+ 1/(x+1)][1+1/(x+2)][1+1/(x+3)][1+1/(x+4)] is (a) (x+5)/(x+1) (b) (x+1)/(x+5) (c) 1+1/(x+5) (d) 1/(x+5)")
The value of [1+ 1/(x+1)][1+1/(x+2)][1+1/(x+3)][1+1/(x+4)] is (a) (x+5)/(x+1) (b) (x+1)/(x+5) (c) 1+1/(x+5) (d) 1/(x+5)
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